Table of Contents
1 Problem
n! means n*(n-1) … 3*2*1
For example, 10! = 10*9 … 3*2*1 = 3628800,
and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.Find the sum of the digits in the number 100!
2 Solution
没什么好说的
3 Answer
648
Source:C++